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145011355401 = 3114394283497
BaseRepresentation
bin1000011100001101011…
…0011010111100001001
3111212022002110002222210
42013003112122330021
54333440401333101
6150341200335333
713322342116623
oct2070326327411
9455262402883
10145011355401
1156554147680
1224130014549
131089cb98353
147039007c13
153b8ab6c7d6
hex21c359af09

145011355401 has 8 divisors (see below), whose sum is σ = 210925607904. Its totient is φ = 87885669920.

The previous prime is 145011355373. The next prime is 145011355469. The reversal of 145011355401 is 104553110541.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 145011355401 - 25 = 145011355369 is a prime.

It is not an unprimeable number, because it can be changed into a prime (145011355471) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2197141716 + ... + 2197141781.

It is an arithmetic number, because the mean of its divisors is an integer number (26365700988).

Almost surely, 2145011355401 is an apocalyptic number.

145011355401 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

145011355401 is a deficient number, since it is larger than the sum of its proper divisors (65914252503).

145011355401 is a wasteful number, since it uses less digits than its factorization.

145011355401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4394283511.

The product of its (nonzero) digits is 6000, while the sum is 30.

Adding to 145011355401 its reverse (104553110541), we get a palindrome (249564465942).

The spelling of 145011355401 in words is "one hundred forty-five billion, eleven million, three hundred fifty-five thousand, four hundred one".

Divisors: 1 3 11 33 4394283497 13182850491 48337118467 145011355401