Search a number
-
+
145013002 = 272506501
BaseRepresentation
bin10001010010010…
…11100100001010
3101002212102102221
420221023210022
5244110404002
622220044254
73410406301
oct1051134412
9332772387
10145013002
1174946462
124069368a
1324074014
141538b438
15cae6c37
hex8a4b90a

145013002 has 4 divisors (see below), whose sum is σ = 217519506. Its totient is φ = 72506500.

The previous prime is 145012981. The next prime is 145013003. The reversal of 145013002 is 200310541.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 200310541 = 1711782973.

It can be written as a sum of positive squares in only one way, i.e., 116186841 + 28826161 = 10779^2 + 5369^2 .

It is not an unprimeable number, because it can be changed into a prime (145013003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 36253249 + ... + 36253252.

Almost surely, 2145013002 is an apocalyptic number.

145013002 is a deficient number, since it is larger than the sum of its proper divisors (72506504).

145013002 is an equidigital number, since it uses as much as digits as its factorization.

145013002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 72506503.

The product of its (nonzero) digits is 120, while the sum is 16.

The square root of 145013002 is about 12042.1344453548. The cubic root of 145013002 is about 525.3744895730.

Adding to 145013002 its reverse (200310541), we get a palindrome (345323543).

The spelling of 145013002 in words is "one hundred forty-five million, thirteen thousand, two".

Divisors: 1 2 72506501 145013002