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145024220110335 = 359668281340689
BaseRepresentation
bin100000111110011000010101…
…000111111001110111111111
3201000111011212020202202022220
4200332120111013321313333
5123002034100322012320
61232235112412340423
742355440240424626
oct4076302507716777
9630434766682286
10145024220110335
114223347652a115
12143227b9a74713
1362bc9575799a7
1427b52d16086bd
1511b762d1cbe40
hex83e6151f9dff

145024220110335 has 8 divisors (see below), whose sum is σ = 232038752176560. Its totient is φ = 77346250725504.

The previous prime is 145024220110331. The next prime is 145024220110433. The reversal of 145024220110335 is 533011022420541.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 145024220110335 - 22 = 145024220110331 is a prime.

It is a super-2 number, since 2×1450242201103352 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 145024220110296 and 145024220110305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (145024220110331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4834140670330 + ... + 4834140670359.

It is an arithmetic number, because the mean of its divisors is an integer number (29004844022070).

Almost surely, 2145024220110335 is an apocalyptic number.

145024220110335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

145024220110335 is a deficient number, since it is larger than the sum of its proper divisors (87014532066225).

145024220110335 is an equidigital number, since it uses as much as digits as its factorization.

145024220110335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9668281340697.

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 145024220110335 its reverse (533011022420541), we get a palindrome (678035242530876).

The spelling of 145024220110335 in words is "one hundred forty-five trillion, twenty-four billion, two hundred twenty million, one hundred ten thousand, three hundred thirty-five".

Divisors: 1 3 5 15 9668281340689 29004844022067 48341406703445 145024220110335