Base | Representation |
---|---|
bin | 100000111110011001001010… |
… | …111001100001110010111011 |
3 | 201000111021012010102022110111 |
4 | 200332121022321201302323 |
5 | 123002042422302430410 |
6 | 1232235342121525151 |
7 | 42355501504131406 |
oct | 4076311271416273 |
9 | 630437163368414 |
10 | 145025122311355 |
11 | 422338998250a0 |
12 | 14322a100437b7 |
13 | 62bca6c464150 |
14 | 27b5379378d3d |
15 | 11b76824e0b8a |
hex | 83e64ae61cbb |
145025122311355 has 32 divisors (see below), whose sum is σ = 209441704909248. Its totient is φ = 94984900147200.
The previous prime is 145025122311271. The next prime is 145025122311361. The reversal of 145025122311355 is 553113221520541.
It is not a de Polignac number, because 145025122311355 - 27 = 145025122311227 is a prime.
It is a super-2 number, since 2×1450251223113552 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2473535794 + ... + 2473594423.
It is an arithmetic number, because the mean of its divisors is an integer number (6545053278414).
Almost surely, 2145025122311355 is an apocalyptic number.
145025122311355 is a deficient number, since it is larger than the sum of its proper divisors (64416582597893).
145025122311355 is a wasteful number, since it uses less digits than its factorization.
145025122311355 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4947130287.
The product of its (nonzero) digits is 180000, while the sum is 40.
Adding to 145025122311355 its reverse (553113221520541), we get a palindrome (698138343831896).
The spelling of 145025122311355 in words is "one hundred forty-five trillion, twenty-five billion, one hundred twenty-two million, three hundred eleven thousand, three hundred fifty-five".
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