Base | Representation |
---|---|
bin | 1000011100010010000… |
… | …1110010001010111010 |
3 | 111212100110121211001202 |
4 | 2013010201302022322 |
5 | 4334010431030404 |
6 | 150343144014202 |
7 | 13323002051303 |
oct | 2070441621272 |
9 | 455313554052 |
10 | 145031111354 |
11 | 56564310608 |
12 | 24136761362 |
13 | 108a3cc466c |
14 | 703b8ab7aa |
15 | 3b8c77121e |
hex | 21c48722ba |
145031111354 has 4 divisors (see below), whose sum is σ = 217546667034. Its totient is φ = 72515555676.
The previous prime is 145031111243. The next prime is 145031111377. The reversal of 145031111354 is 453111130541.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 131765370025 + 13265741329 = 362995^2 + 115177^2 .
It is a super-3 number, since 3×1450311113543 (a number of 34 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 36257777837 + ... + 36257777840.
Almost surely, 2145031111354 is an apocalyptic number.
145031111354 is a deficient number, since it is larger than the sum of its proper divisors (72515555680).
145031111354 is an equidigital number, since it uses as much as digits as its factorization.
145031111354 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 72515555679.
The product of its (nonzero) digits is 3600, while the sum is 29.
Adding to 145031111354 its reverse (453111130541), we get a palindrome (598142241895).
The spelling of 145031111354 in words is "one hundred forty-five billion, thirty-one million, one hundred eleven thousand, three hundred fifty-four".
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