145035233335 has 4 divisors (see below), whose sum is σ = 174042280008. Its totient is φ = 116028186664.

The previous prime is 145035233311. The next prime is 145035233351. The reversal of 145035233335 is 533332530541.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 145035233335 - 2¹³ = 145035225143 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 145035233294 and 145035233303.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14503523329 + ... + 14503523338.

It is an arithmetic number, because the mean of its divisors is an integer number (43510570002).

Almost surely, 2^145035233335 is an apocalyptic number.

145035233335 is a deficient number, since it is larger than the sum of its proper divisors (29007046673).

145035233335 is an equidigital number, since it uses as much as digits as its factorization.

145035233335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29007046672.

The product of its (nonzero) digits is 243000, while the sum is 37.

Adding to 145035233335 its reverse (533332530541), we get a palindrome (678367763876).

The spelling of 145035233335 in words is "one hundred forty-five billion, thirty-five million, two hundred thirty-three thousand, three hundred thirty-five".