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1450365000535 = 51167339183169
BaseRepresentation
bin10101000110110000011…
…111011001101101010111
312010122122102121220201001
4111012300133121231113
5142230321420004120
63030142151244131
7206533253044213
oct25066037315527
95118572556631
101450365000535
1150a107260680
121b5110379647
13a69cc182739
14502ab5cd943
1527ad9aa2e0a
hex151b07d9b57

1450365000535 has 16 divisors (see below), whose sum is σ = 1901480873760. Its totient is φ = 1053243555840.

The previous prime is 1450365000533. The next prime is 1450365000547. The reversal of 1450365000535 is 5350005630541.

It is not a de Polignac number, because 1450365000535 - 21 = 1450365000533 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1450365000494 and 1450365000503.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1450365000533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19554570 + ... + 19628599.

It is an arithmetic number, because the mean of its divisors is an integer number (118842554610).

Almost surely, 21450365000535 is an apocalyptic number.

1450365000535 is a deficient number, since it is larger than the sum of its proper divisors (451115873225).

1450365000535 is a wasteful number, since it uses less digits than its factorization.

1450365000535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 39183858.

The product of its (nonzero) digits is 135000, while the sum is 37.

The spelling of 1450365000535 in words is "one trillion, four hundred fifty billion, three hundred sixty-five million, five hundred thirty-five", and thus it is an aban number.

Divisors: 1 5 11 55 673 3365 7403 37015 39183169 195915845 431014859 2155074295 26370272737 131851363685 290073000107 1450365000535