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14505420143 = 23630670441
BaseRepresentation
bin11011000001001011…
…10010010101101111
31101102220111200200002
431200211302111233
5214201341421033
610355205254515
71022313015434
oct154045622557
941386450602
1014505420143
116173a27935
122989a0443b
1314a2241056
149b867db8b
1559d6bc3e8
hex36097256f

14505420143 has 4 divisors (see below), whose sum is σ = 15136090608. Its totient is φ = 13874749680.

The previous prime is 14505420113. The next prime is 14505420151. The reversal of 14505420143 is 34102450541.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34102450541 = 122927748129.

It is a cyclic number.

It is not a de Polignac number, because 14505420143 - 222 = 14501225839 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14505420113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 315335198 + ... + 315335243.

It is an arithmetic number, because the mean of its divisors is an integer number (3784022652).

Almost surely, 214505420143 is an apocalyptic number.

14505420143 is a deficient number, since it is larger than the sum of its proper divisors (630670465).

14505420143 is an equidigital number, since it uses as much as digits as its factorization.

14505420143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 630670464.

The product of its (nonzero) digits is 9600, while the sum is 29.

Adding to 14505420143 its reverse (34102450541), we get a palindrome (48607870684).

The spelling of 14505420143 in words is "fourteen billion, five hundred five million, four hundred twenty thousand, one hundred forty-three".

Divisors: 1 23 630670441 14505420143