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145110345335 = 529022069067
BaseRepresentation
bin1000011100100101000…
…0000010011001110111
3111212112222201022122122
42013021100002121313
54334141222022320
6150355054150155
713324653404204
oct2071120023167
9455488638578
10145110345335
11565a500923a
12241591b235b
13108b7547187
147048214cab
153b946c2d25
hex21c9402677

145110345335 has 4 divisors (see below), whose sum is σ = 174132414408. Its totient is φ = 116088276264.

The previous prime is 145110345313. The next prime is 145110345409. The reversal of 145110345335 is 533543011541.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 145110345335 - 210 = 145110344311 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 145110345295 and 145110345304.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14511034529 + ... + 14511034538.

It is an arithmetic number, because the mean of its divisors is an integer number (43533103602).

Almost surely, 2145110345335 is an apocalyptic number.

145110345335 is a deficient number, since it is larger than the sum of its proper divisors (29022069073).

145110345335 is an equidigital number, since it uses as much as digits as its factorization.

145110345335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29022069072.

The product of its (nonzero) digits is 54000, while the sum is 35.

Adding to 145110345335 its reverse (533543011541), we get a palindrome (678653356876).

The spelling of 145110345335 in words is "one hundred forty-five billion, one hundred ten million, three hundred forty-five thousand, three hundred thirty-five".

Divisors: 1 5 29022069067 145110345335