145112054431 has 4 divisors (see below), whose sum is σ = 152749531000. Its totient is φ = 137474577864.

The previous prime is 145112054419. The next prime is 145112054459. The reversal of 145112054431 is 134450211541.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 145112054431 - 2⁷ = 145112054303 is a prime.

It is a super-2 number, since 2×145112054431² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 145112054393 and 145112054402.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (145112054831) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3818738256 + ... + 3818738293.

It is an arithmetic number, because the mean of its divisors is an integer number (38187382750).

Almost surely, 2^145112054431 is an apocalyptic number.

145112054431 is a deficient number, since it is larger than the sum of its proper divisors (7637476569).

145112054431 is an equidigital number, since it uses as much as digits as its factorization.

145112054431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7637476568.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 145112054431 its reverse (134450211541), we get a palindrome (279562265972).

The spelling of 145112054431 in words is "one hundred forty-five billion, one hundred twelve million, fifty-four thousand, four hundred thirty-one".