145112413441 has 4 divisors (see below), whose sum is σ = 151421648832. Its totient is φ = 138803178052.

The previous prime is 145112413393. The next prime is 145112413471. The reversal of 145112413441 is 144314211541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 144314211541 = 3181 ⋅45367561.

It is a cyclic number.

It is not a de Polignac number, because 145112413441 - 2¹⁷ = 145112282369 is a prime.

It is a super-2 number, since 2×145112413441² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (145112413471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3154617661 + ... + 3154617706.

It is an arithmetic number, because the mean of its divisors is an integer number (37855412208).

Almost surely, 2^145112413441 is an apocalyptic number.

It is an amenable number.

145112413441 is a deficient number, since it is larger than the sum of its proper divisors (6309235391).

145112413441 is an equidigital number, since it uses as much as digits as its factorization.

145112413441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6309235390.

The product of its digits is 7680, while the sum is 31.

Adding to 145112413441 its reverse (144314211541), we get a palindrome (289426624982).

The spelling of 145112413441 in words is "one hundred forty-five billion, one hundred twelve million, four hundred thirteen thousand, four hundred forty-one".