145112413471 has 2 divisors, whose sum is σ = 145112413472. Its totient is φ = 145112413470.

The previous prime is 145112413393. The next prime is 145112413549. The reversal of 145112413471 is 174314211541.

It is a balanced prime because it is at equal distance from previous prime (145112413393) and next prime (145112413549).

It is a cyclic number.

It is not a de Polignac number, because 145112413471 - 2¹³ = 145112405279 is a prime.

It is a super-3 number, since 3×145112413471³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (145112413571) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72556206735 + 72556206736.

It is an arithmetic number, because the mean of its divisors is an integer number (72556206736).

Almost surely, 2^145112413471 is an apocalyptic number.

145112413471 is a deficient number, since it is larger than the sum of its proper divisors (1).

145112413471 is an equidigital number, since it uses as much as digits as its factorization.

145112413471 is an evil number, because the sum of its binary digits is even.

The product of its digits is 13440, while the sum is 34.

The spelling of 145112413471 in words is "one hundred forty-five billion, one hundred twelve million, four hundred thirteen thousand, four hundred seventy-one".