Base | Representation |
---|---|
bin | 1000011100101000000… |
… | …0011101111110000001 |
3 | 111212120212121100001010 |
4 | 2013022000131332001 |
5 | 4334202444304103 |
6 | 150400230231133 |
7 | 13325166332226 |
oct | 2071200357601 |
9 | 455525540033 |
10 | 145123041153 |
11 | 5660119a852 |
12 | 241614b54a9 |
13 | 108ba070aac |
14 | 7049b9b94d |
15 | 3b9587e903 |
hex | 21ca01df81 |
145123041153 has 4 divisors (see below), whose sum is σ = 193497388208. Its totient is φ = 96748694100.
The previous prime is 145123041149. The next prime is 145123041179. The reversal of 145123041153 is 351140321541.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 145123041153 - 22 = 145123041149 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 145123041153.
It is not an unprimeable number, because it can be changed into a prime (145123041053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24187173523 + ... + 24187173528.
It is an arithmetic number, because the mean of its divisors is an integer number (48374347052).
Almost surely, 2145123041153 is an apocalyptic number.
It is an amenable number.
145123041153 is a deficient number, since it is larger than the sum of its proper divisors (48374347055).
145123041153 is an equidigital number, since it uses as much as digits as its factorization.
145123041153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 48374347054.
The product of its (nonzero) digits is 7200, while the sum is 30.
Adding to 145123041153 its reverse (351140321541), we get a palindrome (496263362694).
The spelling of 145123041153 in words is "one hundred forty-five billion, one hundred twenty-three million, forty-one thousand, one hundred fifty-three".
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