Base | Representation |
---|---|
bin | 100000111111110110100101… |
… | …010011100011011111110010 |
3 | 201000211212002021111001110120 |
4 | 200333312211103203133302 |
5 | 123010213331333100224 |
6 | 1232353411000511110 |
7 | 42365652164545206 |
oct | 4077664523433762 |
9 | 630755067431416 |
10 | 145125423331314 |
11 | 4227238a070a18 |
12 | 1433a34277b496 |
13 | 62c936543a9ba |
14 | 27ba172396b06 |
15 | 11ba0a2d8b779 |
hex | 83fda54e37f2 |
145125423331314 has 16 divisors (see below), whose sum is σ = 290832511692000. Its totient is φ = 48278196938880.
The previous prime is 145125423331313. The next prime is 145125423331319. The reversal of 145125423331314 is 413133324521541.
It is a super-2 number, since 2×1451254233313142 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (145125423331313) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24236039647 + ... + 24236045634.
It is an arithmetic number, because the mean of its divisors is an integer number (18177031980750).
Almost surely, 2145125423331314 is an apocalyptic number.
145125423331314 is an abundant number, since it is smaller than the sum of its proper divisors (145707088360686).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
145125423331314 is a wasteful number, since it uses less digits than its factorization.
145125423331314 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 48472085785.
The product of its digits is 518400, while the sum is 42.
Adding to 145125423331314 its reverse (413133324521541), we get a palindrome (558258747852855).
The spelling of 145125423331314 in words is "one hundred forty-five trillion, one hundred twenty-five billion, four hundred twenty-three million, three hundred thirty-one thousand, three hundred fourteen".
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