Base | Representation |
---|---|
bin | 1101001100110001001101… |
… | …1111101001001011110001 |
3 | 1220101102122102111012222012 |
4 | 3103030103133221023301 |
5 | 3400240132004233231 |
6 | 50511105015252305 |
7 | 3025350126542423 |
oct | 323142337511361 |
9 | 56342572435865 |
10 | 14513021555441 |
11 | 4695a35350452 |
12 | 176487967a095 |
13 | 813758a7cac6 |
14 | 382610c2c813 |
15 | 1a27b4cdee2b |
hex | d33137e92f1 |
14513021555441 has 8 divisors (see below), whose sum is σ = 14516855220000. Its totient is φ = 14509188401760.
The previous prime is 14513021555401. The next prime is 14513021555477. The reversal of 14513021555441 is 14455512031541.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14513021555441 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14513021555401) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 60427010 + ... + 60666708.
It is an arithmetic number, because the mean of its divisors is an integer number (1814606902500).
Almost surely, 214513021555441 is an apocalyptic number.
It is an amenable number.
14513021555441 is a deficient number, since it is larger than the sum of its proper divisors (3833664559).
14513021555441 is an equidigital number, since it uses as much as digits as its factorization.
14513021555441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 255439.
The product of its (nonzero) digits is 240000, while the sum is 41.
Adding to 14513021555441 its reverse (14455512031541), we get a palindrome (28968533586982).
The spelling of 14513021555441 in words is "fourteen trillion, five hundred thirteen billion, twenty-one million, five hundred fifty-five thousand, four hundred forty-one".
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