14513021555401 has 2 divisors, whose sum is σ = 14513021555402. Its totient is φ = 14513021555400.

The previous prime is 14513021555369. The next prime is 14513021555477. The reversal of 14513021555401 is 10455512031541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11617497318025 + 2895524237376 = 3408445^2 + 1701624^2 .

It is a cyclic number.

It is not a de Polignac number, because 14513021555401 - 2⁵ = 14513021555369 is a prime.

It is a super-2 number, since 2×14513021555401² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14513021535401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7256510777700 + 7256510777701.

It is an arithmetic number, because the mean of its divisors is an integer number (7256510777701).

Almost surely, 2^{14513021555401} is an apocalyptic number.

It is an amenable number.

14513021555401 is a deficient number, since it is larger than the sum of its proper divisors (1).

14513021555401 is an equidigital number, since it uses as much as digits as its factorization.

14513021555401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60000, while the sum is 37.

Adding to 14513021555401 its reverse (10455512031541), we get a palindrome (24968533586942).

The spelling of 14513021555401 in words is "fourteen trillion, five hundred thirteen billion, twenty-one million, five hundred fifty-five thousand, four hundred one".