145133505331541 has 4 divisors (see below), whose sum is σ = 145134736322784. Its totient is φ = 145132274340300.

The previous prime is 145133505331531. The next prime is 145133505331613.

145133505331541 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-145133505331541 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 145133505331492 and 145133505331501.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (145133505331531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 615318755 + ... + 615554576.

It is an arithmetic number, because the mean of its divisors is an integer number (36283684080696).

Almost surely, 2^{145133505331541} is an apocalyptic number.

It is an amenable number.

145133505331541 is a deficient number, since it is larger than the sum of its proper divisors (1230991243).

145133505331541 is a wasteful number, since it uses less digits than its factorization.

145133505331541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1230991242.

The product of its (nonzero) digits is 810000, while the sum is 44.

It can be divided in two parts, 14513350 and 5331541, that added together give a palindrome (19844891).

The spelling of 145133505331541 in words is "one hundred forty-five trillion, one hundred thirty-three billion, five hundred five million, three hundred thirty-one thousand, five hundred forty-one".