1452134131 has 4 divisors (see below), whose sum is σ = 1659581872. Its totient is φ = 1244686392.

The previous prime is 1452134107. The next prime is 1452134143. The reversal of 1452134131 is 1314312541.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1314312541 = 6863 ⋅191507.

It is a cyclic number.

It is not a de Polignac number, because 1452134131 - 2¹¹ = 1452132083 is a prime.

It is a super-2 number, since 2×1452134131² = 4217387068830250322, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1452134096 and 1452134105.

It is not an unprimeable number, because it can be changed into a prime (1452134531) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 103723860 + ... + 103723873.

It is an arithmetic number, because the mean of its divisors is an integer number (414895468).

Almost surely, 2^1452134131 is an apocalyptic number.

1452134131 is a deficient number, since it is larger than the sum of its proper divisors (207447741).

1452134131 is an equidigital number, since it uses as much as digits as its factorization.

1452134131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 207447740.

The product of its digits is 1440, while the sum is 25.

The square root of 1452134131 is about 38106.8777388020. The cubic root of 1452134131 is about 1132.4062154176.

Adding to 1452134131 its reverse (1314312541), we get a palindrome (2766446672).

The spelling of 1452134131 in words is "one billion, four hundred fifty-two million, one hundred thirty-four thousand, one hundred thirty-one".