Base | Representation |
---|---|
bin | 1000011101000000001… |
… | …0100001010011110111 |
3 | 111212211221000220002022 |
4 | 2013100002201103313 |
5 | 4334404401224143 |
6 | 150414243303355 |
7 | 13330535456531 |
oct | 2072002412367 |
9 | 455757026068 |
10 | 145224242423 |
11 | 56653331867 |
12 | 2418b37ab5b |
13 | 109050152c0 |
14 | 70593c2851 |
15 | 3b9e6c0268 |
hex | 21d00a14f7 |
145224242423 has 4 divisors (see below), whose sum is σ = 156395338008. Its totient is φ = 134053146840.
The previous prime is 145224242419. The next prime is 145224242441. The reversal of 145224242423 is 324242422541.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 145224242423 - 22 = 145224242419 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (145224242623) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5585547773 + ... + 5585547798.
It is an arithmetic number, because the mean of its divisors is an integer number (39098834502).
Almost surely, 2145224242423 is an apocalyptic number.
145224242423 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
145224242423 is a deficient number, since it is larger than the sum of its proper divisors (11171095585).
145224242423 is a wasteful number, since it uses less digits than its factorization.
145224242423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11171095584.
The product of its digits is 122880, while the sum is 35.
Adding to 145224242423 its reverse (324242422541), we get a palindrome (469466664964).
The spelling of 145224242423 in words is "one hundred forty-five billion, two hundred twenty-four million, two hundred forty-two thousand, four hundred twenty-three".
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