14524004113 has 4 divisors (see below), whose sum is σ = 14607958068. Its totient is φ = 14440050160.

The previous prime is 14524004107. The next prime is 14524004137. The reversal of 14524004113 is 31140042541.

14524004113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 13265741329 + 1258262784 = 115177^2 + 35472^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14524004113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14564004113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41976718 + ... + 41977063.

It is an arithmetic number, because the mean of its divisors is an integer number (3651989517).

Almost surely, 2^14524004113 is an apocalyptic number.

It is an amenable number.

14524004113 is a deficient number, since it is larger than the sum of its proper divisors (83953955).

14524004113 is an equidigital number, since it uses as much as digits as its factorization.

14524004113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 83953954.

The product of its (nonzero) digits is 1920, while the sum is 25.

Adding to 14524004113 its reverse (31140042541), we get a palindrome (45664046654).

The spelling of 14524004113 in words is "fourteen billion, five hundred twenty-four million, four thousand, one hundred thirteen".