145260019543 has 4 divisors (see below), whose sum is σ = 145264408128. Its totient is φ = 145255630960.

The previous prime is 145260019519. The next prime is 145260019549. The reversal of 145260019543 is 345910062541.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 345910062541 = 10301 ⋅33580241.

It is a cyclic number.

It is not a de Polignac number, because 145260019543 - 2³³ = 136670084951 is a prime.

It is a super-2 number, since 2×145260019543² (a number of 23 digits) contains 22 as substring.

It is a Smith number, since the sum of its digits (40) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 145260019496 and 145260019505.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (145260019549) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2144263 + ... + 2210968.

It is an arithmetic number, because the mean of its divisors is an integer number (36316102032).

Almost surely, 2^145260019543 is an apocalyptic number.

145260019543 is a deficient number, since it is larger than the sum of its proper divisors (4388585).

145260019543 is an equidigital number, since it uses as much as digits as its factorization.

145260019543 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4388584.

The product of its (nonzero) digits is 129600, while the sum is 40.

The spelling of 145260019543 in words is "one hundred forty-five billion, two hundred sixty million, nineteen thousand, five hundred forty-three".