Base | Representation |
---|---|
bin | 1000011101010101100… |
… | …1110011111110111101 |
3 | 111220002012100221201211 |
4 | 2013111121303332331 |
5 | 4340100420444201 |
6 | 150431220204421 |
7 | 13333010416525 |
oct | 2072531637675 |
9 | 456065327654 |
10 | 145314234301 |
11 | 5669a108015 |
12 | 241b5539711 |
13 | 1091a863632 |
14 | 706732a685 |
15 | 3ba7549651 |
hex | 21d5673fbd |
145314234301 has 4 divisors (see below), whose sum is σ = 151632244512. Its totient is φ = 138996224092.
The previous prime is 145314234283. The next prime is 145314234341. The reversal of 145314234301 is 103432413541.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 145314234301 - 27 = 145314234173 is a prime.
It is a super-2 number, since 2×1453142343012 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (145314234341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3159005071 + ... + 3159005116.
It is an arithmetic number, because the mean of its divisors is an integer number (37908061128).
Almost surely, 2145314234301 is an apocalyptic number.
It is an amenable number.
145314234301 is a deficient number, since it is larger than the sum of its proper divisors (6318010211).
145314234301 is an equidigital number, since it uses as much as digits as its factorization.
145314234301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6318010210.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 145314234301 its reverse (103432413541), we get a palindrome (248746647842).
The spelling of 145314234301 in words is "one hundred forty-five billion, three hundred fourteen million, two hundred thirty-four thousand, three hundred one".
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