145320401041 has 4 divisors (see below), whose sum is σ = 145437880372. Its totient is φ = 145202921712.

The previous prime is 145320401033. The next prime is 145320401047. The reversal of 145320401041 is 140104023541.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 86330192400 + 58990208641 = 293820^2 + 242879^2 .

It is a cyclic number.

It is not a de Polignac number, because 145320401041 - 2³ = 145320401033 is a prime.

It is a super-2 number, since 2×145320401041² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 145320400997 and 145320401015.

It is not an unprimeable number, because it can be changed into a prime (145320401047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58737810 + ... + 58740283.

It is an arithmetic number, because the mean of its divisors is an integer number (36359470093).

Almost surely, 2^145320401041 is an apocalyptic number.

It is an amenable number.

145320401041 is a deficient number, since it is larger than the sum of its proper divisors (117479331).

145320401041 is a wasteful number, since it uses less digits than its factorization.

145320401041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 117479330.

The product of its (nonzero) digits is 1920, while the sum is 25.

Adding to 145320401041 its reverse (140104023541), we get a palindrome (285424424582).

The spelling of 145320401041 in words is "one hundred forty-five billion, three hundred twenty million, four hundred one thousand, forty-one".