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145325325113 = 1732721130871
BaseRepresentation
bin1000011101011000010…
…0000111101100111001
3111220002222020102110122
42013112010013230321
54340111240400423
6150432254023025
713333203611333
oct2072604075471
9456088212418
10145325325113
11566a53a2781
12241b91a7a75
131091cc47847
1470689b6453
153ba84da8c8
hex21d6107b39

145325325113 has 8 divisors (see below), whose sum is σ = 146175462336. Its totient is φ = 144475304400.

The previous prime is 145325325097. The next prime is 145325325121. The reversal of 145325325113 is 311523523541.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 145325325113 - 24 = 145325325097 is a prime.

It is a super-2 number, since 2×1453253251132 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (145325325133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4692068 + ... + 4722938.

It is an arithmetic number, because the mean of its divisors is an integer number (18271932792).

Almost surely, 2145325325113 is an apocalyptic number.

It is an amenable number.

145325325113 is a deficient number, since it is larger than the sum of its proper divisors (850137223).

145325325113 is a wasteful number, since it uses less digits than its factorization.

145325325113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 58255.

The product of its digits is 54000, while the sum is 35.

Adding to 145325325113 its reverse (311523523541), we get a palindrome (456848848654).

The spelling of 145325325113 in words is "one hundred forty-five billion, three hundred twenty-five million, three hundred twenty-five thousand, one hundred thirteen".

Divisors: 1 173 27211 30871 4707503 5340683 840030781 145325325113