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145331450051 = 1131286119027
BaseRepresentation
bin1000011101011001101…
…1011111000011000011
3111220010101202121022012
42013112123133003003
54340114322400201
6150433033203135
713333306641314
oct2072633370303
9456111677265
10145331450051
11566a88a6507
12241bb2604ab
13109212b0678
14706972c60b
153ba8cea5bb
hex21d66df0c3

145331450051 has 4 divisors (see below), whose sum is σ = 146617569192. Its totient is φ = 144045330912.

The previous prime is 145331450039. The next prime is 145331450101. The reversal of 145331450051 is 150054133541.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-145331450051 is a prime.

It is a super-2 number, since 2×1453314500512 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (145331410051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 643059401 + ... + 643059626.

It is an arithmetic number, because the mean of its divisors is an integer number (36654392298).

Almost surely, 2145331450051 is an apocalyptic number.

145331450051 is a deficient number, since it is larger than the sum of its proper divisors (1286119141).

145331450051 is a wasteful number, since it uses less digits than its factorization.

145331450051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1286119140.

The product of its (nonzero) digits is 18000, while the sum is 32.

Adding to 145331450051 its reverse (150054133541), we get a palindrome (295385583592).

The spelling of 145331450051 in words is "one hundred forty-five billion, three hundred thirty-one million, four hundred fifty thousand, fifty-one".

Divisors: 1 113 1286119027 145331450051