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145335504154113 = 32713181409978203
BaseRepresentation
bin100001000010111010001111…
…000110010010111000000001
3201001120221100011121121010100
4201002322033012102320001
5123022134103030412423
61233034113041553013
742420100164225150
oct4102721706227001
9631527304547110
10145335504154113
114234349422a529
1214372bb2345769
136313105105080
1427c63c1239597
1511c079b336343
hex842e8f192e01

145335504154113 has 48 divisors (see below), whose sum is σ = 258375918003840. Its totient is φ = 76659984755712.

The previous prime is 145335504154109. The next prime is 145335504154249. The reversal of 145335504154113 is 311451405533541.

145335504154113 is a `hidden beast` number, since 1 + 4 + 5 + 3 + 3 + 5 + 50 + 41 + 541 + 13 = 666.

It is not a de Polignac number, because 145335504154113 - 22 = 145335504154109 is a prime.

It is a super-2 number, since 2×1453355041541132 (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (145335504134113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 148084870 + ... + 149063072.

It is an arithmetic number, because the mean of its divisors is an integer number (5382831625080).

Almost surely, 2145335504154113 is an apocalyptic number.

145335504154113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

145335504154113 is a deficient number, since it is larger than the sum of its proper divisors (113040413849727).

145335504154113 is a wasteful number, since it uses less digits than its factorization.

145335504154113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1159638 (or 1159635 counting only the distinct ones).

The product of its (nonzero) digits is 1080000, while the sum is 45.

Adding to 145335504154113 its reverse (311451405533541), we get a palindrome (456786909687654).

The spelling of 145335504154113 in words is "one hundred forty-five trillion, three hundred thirty-five billion, five hundred four million, one hundred fifty-four thousand, one hundred thirteen".

Divisors: 1 3 7 9 13 21 39 63 91 117 273 819 181409 544227 978203 1269863 1632681 2358317 2934609 3809589 6847421 7074951 8803827 11428767 12716639 16508219 20542263 21224853 38149917 49524657 61626789 89016473 114449751 148573971 267049419 801148257 177454828027 532364484081 1242183796189 1597093452243 2306912764351 3726551388567 6920738293053 11179654165701 16148389350457 20762214879159 48445168051371 145335504154113