Base | Representation |
---|---|
bin | 100001000010111010001111… |
… | …000110010010111000000001 |
3 | 201001120221100011121121010100 |
4 | 201002322033012102320001 |
5 | 123022134103030412423 |
6 | 1233034113041553013 |
7 | 42420100164225150 |
oct | 4102721706227001 |
9 | 631527304547110 |
10 | 145335504154113 |
11 | 4234349422a529 |
12 | 14372bb2345769 |
13 | 6313105105080 |
14 | 27c63c1239597 |
15 | 11c079b336343 |
hex | 842e8f192e01 |
145335504154113 has 48 divisors (see below), whose sum is σ = 258375918003840. Its totient is φ = 76659984755712.
The previous prime is 145335504154109. The next prime is 145335504154249. The reversal of 145335504154113 is 311451405533541.
145335504154113 is a `hidden beast` number, since 1 + 4 + 5 + 3 + 3 + 5 + 50 + 41 + 541 + 13 = 666.
It is not a de Polignac number, because 145335504154113 - 22 = 145335504154109 is a prime.
It is a super-2 number, since 2×1453355041541132 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (145335504134113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 148084870 + ... + 149063072.
It is an arithmetic number, because the mean of its divisors is an integer number (5382831625080).
Almost surely, 2145335504154113 is an apocalyptic number.
145335504154113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
145335504154113 is a deficient number, since it is larger than the sum of its proper divisors (113040413849727).
145335504154113 is a wasteful number, since it uses less digits than its factorization.
145335504154113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1159638 (or 1159635 counting only the distinct ones).
The product of its (nonzero) digits is 1080000, while the sum is 45.
Adding to 145335504154113 its reverse (311451405533541), we get a palindrome (456786909687654).
The spelling of 145335504154113 in words is "one hundred forty-five trillion, three hundred thirty-five billion, five hundred four million, one hundred fifty-four thousand, one hundred thirteen".
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