Base | Representation |
---|---|
bin | 11011000100100101… |
… | …10110110110111111 |
3 | 1101111220022022210202 |
4 | 31202102312312333 |
5 | 214231201343401 |
6 | 10402110154115 |
7 | 1023111031565 |
oct | 154222666677 |
9 | 41456268722 |
10 | 14534012351 |
11 | 6189086661 |
12 | 29974b293b |
13 | 14a8142311 |
14 | 9bc3a3a35 |
15 | 5a0e6906b |
hex | 3624b6dbf |
14534012351 has 4 divisors (see below), whose sum is σ = 15388954272. Its totient is φ = 13679070432.
The previous prime is 14534012327. The next prime is 14534012369. The reversal of 14534012351 is 15321043541.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14534012351 is a prime.
It is a super-2 number, since 2×145340123512 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14534012371) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 427470935 + ... + 427470968.
It is an arithmetic number, because the mean of its divisors is an integer number (3847238568).
Almost surely, 214534012351 is an apocalyptic number.
14534012351 is a deficient number, since it is larger than the sum of its proper divisors (854941921).
14534012351 is an equidigital number, since it uses as much as digits as its factorization.
14534012351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 854941920.
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 14534012351 its reverse (15321043541), we get a palindrome (29855055892).
The spelling of 14534012351 in words is "fourteen billion, five hundred thirty-four million, twelve thousand, three hundred fifty-one".
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