Base | Representation |
---|---|
bin | 11011000100100110… |
… | …10100100101100011 |
3 | 1101111220112111211112 |
4 | 31202103110211203 |
5 | 214231214242430 |
6 | 10402112533535 |
7 | 1023112046564 |
oct | 154223244543 |
9 | 41456474745 |
10 | 14534134115 |
11 | 618915a096 |
12 | 29975512ab |
13 | 14a8185877 |
14 | 9bc3d616b |
15 | 5a0e90195 |
hex | 3624d4963 |
14534134115 has 4 divisors (see below), whose sum is σ = 17440960944. Its totient is φ = 11627307288.
The previous prime is 14534134051. The next prime is 14534134123. The reversal of 14534134115 is 51143143541.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 51143143541 = 7 ⋅7306163363.
It is a cyclic number.
It is not a de Polignac number, because 14534134115 - 26 = 14534134051 is a prime.
It is a super-2 number, since 2×145341341152 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1453413407 + ... + 1453413416.
It is an arithmetic number, because the mean of its divisors is an integer number (4360240236).
Almost surely, 214534134115 is an apocalyptic number.
14534134115 is a deficient number, since it is larger than the sum of its proper divisors (2906826829).
14534134115 is an equidigital number, since it uses as much as digits as its factorization.
14534134115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2906826828.
The product of its digits is 14400, while the sum is 32.
Adding to 14534134115 its reverse (51143143541), we get a palindrome (65677277656).
The spelling of 14534134115 in words is "fourteen billion, five hundred thirty-four million, one hundred thirty-four thousand, one hundred fifteen".
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