Base | Representation |
---|---|
bin | 10101001001100110110… |
… | …101111010010000000111 |
3 | 12010221112122100012010011 |
4 | 111021212311322100013 |
5 | 142303103113314221 |
6 | 3031405520011051 |
7 | 210002132113036 |
oct | 25114665722007 |
9 | 5127478305104 |
10 | 1453424354311 |
11 | 510437180426 |
12 | 1b5824a60a87 |
13 | a7098c48a47 |
14 | 504bba4671d |
15 | 27c1846d1e1 |
hex | 15266d7a407 |
1453424354311 has 4 divisors (see below), whose sum is σ = 1459505628000. Its totient is φ = 1447343080624.
The previous prime is 1453424354243. The next prime is 1453424354329. The reversal of 1453424354311 is 1134534243541.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1453424354311 - 213 = 1453424346119 is a prime.
It is a super-2 number, since 2×14534243543112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1453424354411) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3040636486 + ... + 3040636963.
It is an arithmetic number, because the mean of its divisors is an integer number (364876407000).
Almost surely, 21453424354311 is an apocalyptic number.
1453424354311 is a deficient number, since it is larger than the sum of its proper divisors (6081273689).
1453424354311 is an equidigital number, since it uses as much as digits as its factorization.
1453424354311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6081273688.
The product of its digits is 345600, while the sum is 40.
Adding to 1453424354311 its reverse (1134534243541), we get a palindrome (2587958597852).
The spelling of 1453424354311 in words is "one trillion, four hundred fifty-three billion, four hundred twenty-four million, three hundred fifty-four thousand, three hundred eleven".
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