145343343541 has 4 divisors (see below), whose sum is σ = 158556374784. Its totient is φ = 132130312300.

The previous prime is 145343343517. The next prime is 145343343547.

145343343541 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 145343343541 - 2⁷ = 145343343413 is a prime.

It is a super-2 number, since 2×145343343541² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 145343343494 and 145343343503.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (145343343547) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6606515605 + ... + 6606515626.

It is an arithmetic number, because the mean of its divisors is an integer number (39639093696).

Almost surely, 2^145343343541 is an apocalyptic number.

145343343541 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

145343343541 is a deficient number, since it is larger than the sum of its proper divisors (13213031243).

145343343541 is a wasteful number, since it uses less digits than its factorization.

145343343541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13213031242.

The product of its digits is 518400, while the sum is 40.

It can be divided in two parts, 145343 and 343541, that added together give a palindrome (488884).

The spelling of 145343343541 in words is "one hundred forty-five billion, three hundred forty-three million, three hundred forty-three thousand, five hundred forty-one".