145346233 has 4 divisors (see below), whose sum is σ = 145370368. Its totient is φ = 145322100.

The previous prime is 145346213. The next prime is 145346261. The reversal of 145346233 is 332643541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 332643541 = 139 ⋅2393119.

It is a cyclic number.

It is not a de Polignac number, because 145346233 - 2⁹ = 145345721 is a prime.

It is a super-2 number, since 2×145346233² = 42251054894580578, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 145346195 and 145346204.

It is not an unprimeable number, because it can be changed into a prime (145346213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5260 + ... + 17842.

It is an arithmetic number, because the mean of its divisors is an integer number (36342592).

Almost surely, 2^145346233 is an apocalyptic number.

It is an amenable number.

145346233 is a deficient number, since it is larger than the sum of its proper divisors (24135).

145346233 is a wasteful number, since it uses less digits than its factorization.

145346233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24134.

The product of its digits is 25920, while the sum is 31.

The square root of 145346233 is about 12055.9625497096. The cubic root of 145346233 is about 525.7766078525.

Adding to 145346233 its reverse (332643541), we get a palindrome (477989774).

The spelling of 145346233 in words is "one hundred forty-five million, three hundred forty-six thousand, two hundred thirty-three".