145352585253541 has 4 divisors (see below), whose sum is σ = 145352611613772. Its totient is φ = 145352558893312.

The previous prime is 145352585253527. The next prime is 145352585253599.

145352585253541 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 88882545484516 + 56470039769025 = 9427754^2 + 7514655^2 .

It is a cyclic number.

It is not a de Polignac number, because 145352585253541 - 2⁵ = 145352585253509 is a prime.

It is a super-3 number, since 3×145352585253541³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (145352585253641) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1398460 + ... + 17107333.

It is an arithmetic number, because the mean of its divisors is an integer number (36338152903443).

Almost surely, 2^{145352585253541} is an apocalyptic number.

It is an amenable number.

145352585253541 is a deficient number, since it is larger than the sum of its proper divisors (26360231).

145352585253541 is an equidigital number, since it uses as much as digits as its factorization.

145352585253541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26360230.

The product of its digits is 72000000, while the sum is 58.

The spelling of 145352585253541 in words is "one hundred forty-five trillion, three hundred fifty-two billion, five hundred eighty-five million, two hundred fifty-three thousand, five hundred forty-one".