Base | Representation |
---|---|
bin | 11011000100110000… |
… | …01100010111010001 |
3 | 1101111222221101121020 |
4 | 31202120030113101 |
5 | 214232031124103 |
6 | 10402200150053 |
7 | 1023125645664 |
oct | 154230142721 |
9 | 41458841536 |
10 | 14535411153 |
11 | 618995159a |
12 | 2997a68329 |
13 | 14a8511c03 |
14 | 9bc6496db |
15 | 5a1143753 |
hex | 36260c5d1 |
14535411153 has 4 divisors (see below), whose sum is σ = 19380548208. Its totient is φ = 9690274100.
The previous prime is 14535411127. The next prime is 14535411197. The reversal of 14535411153 is 35111453541.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14535411153 - 210 = 14535410129 is a prime.
It is a super-2 number, since 2×145354111532 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (14535411353) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2422568523 + ... + 2422568528.
It is an arithmetic number, because the mean of its divisors is an integer number (4845137052).
Almost surely, 214535411153 is an apocalyptic number.
It is an amenable number.
14535411153 is a deficient number, since it is larger than the sum of its proper divisors (4845137055).
14535411153 is an equidigital number, since it uses as much as digits as its factorization.
14535411153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4845137054.
The product of its digits is 18000, while the sum is 33.
Adding to 14535411153 its reverse (35111453541), we get a palindrome (49646864694).
The spelling of 14535411153 in words is "fourteen billion, five hundred thirty-five million, four hundred eleven thousand, one hundred fifty-three".
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