Base | Representation |
---|---|
bin | 1000011101011111010… |
… | …1011000001111100111 |
3 | 111220012001002211112101 |
4 | 2013113311120033213 |
5 | 4340141340441033 |
6 | 150435234232531 |
7 | 13334014146232 |
oct | 2072765301747 |
9 | 456161084471 |
10 | 145355015143 |
11 | 56710131298 |
12 | 24207125747 |
13 | 10926141700 |
14 | 706c904419 |
15 | 3baae0297d |
hex | 21d7d583e7 |
145355015143 has 12 divisors (see below), whose sum is σ = 159552385680. Its totient is φ = 132335850816.
The previous prime is 145355015137. The next prime is 145355015147. The reversal of 145355015143 is 341510553541.
It is not a de Polignac number, because 145355015143 - 217 = 145354884071 is a prime.
It is a super-2 number, since 2×1453550151432 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (145355015147) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5878683 + ... + 5903356.
It is an arithmetic number, because the mean of its divisors is an integer number (13296032140).
Almost surely, 2145355015143 is an apocalyptic number.
145355015143 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
145355015143 is a deficient number, since it is larger than the sum of its proper divisors (14197370537).
145355015143 is a wasteful number, since it uses less digits than its factorization.
145355015143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11782138 (or 11782125 counting only the distinct ones).
The product of its (nonzero) digits is 90000, while the sum is 37.
Adding to 145355015143 its reverse (341510553541), we get a palindrome (486865568684).
The spelling of 145355015143 in words is "one hundred forty-five billion, three hundred fifty-five million, fifteen thousand, one hundred forty-three".
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