Base | Representation |
---|---|
bin | 11011000100110101… |
… | …10101110101110011 |
3 | 1101112001020122211112 |
4 | 31202122311311303 |
5 | 214232220332311 |
6 | 10402223103535 |
7 | 1023134566556 |
oct | 154232656563 |
9 | 41461218745 |
10 | 14536105331 |
11 | 618a2860a0 |
12 | 2998141bab |
13 | 14a86c5b77 |
14 | 9bc78a69d |
15 | 5a122e28b |
hex | 3626b5d73 |
14536105331 has 4 divisors (see below), whose sum is σ = 15857569464. Its totient is φ = 13214641200.
The previous prime is 14536105321. The next prime is 14536105343. The reversal of 14536105331 is 13350163541.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14536105331 - 218 = 14535843187 is a prime.
It is a super-2 number, since 2×145361053312 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (14536105301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 660732050 + ... + 660732071.
It is an arithmetic number, because the mean of its divisors is an integer number (3964392366).
Almost surely, 214536105331 is an apocalyptic number.
14536105331 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
14536105331 is a deficient number, since it is larger than the sum of its proper divisors (1321464133).
14536105331 is a wasteful number, since it uses less digits than its factorization.
14536105331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1321464132.
The product of its (nonzero) digits is 16200, while the sum is 32.
Adding to 14536105331 its reverse (13350163541), we get a palindrome (27886268872).
The spelling of 14536105331 in words is "fourteen billion, five hundred thirty-six million, one hundred five thousand, three hundred thirty-one".
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