14540040131 has 4 divisors (see below), whose sum is σ = 14540769600. Its totient is φ = 14539310664.

The previous prime is 14540040113. The next prime is 14540040133. The reversal of 14540040131 is 13104004541.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13104004541 = 74611 ⋅175631.

It is a cyclic number.

It is not a de Polignac number, because 14540040131 - 2²⁶ = 14472931267 is a prime.

It is a super-2 number, since 2×14540040131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14540040097 and 14540040106.

It is not an unprimeable number, because it can be changed into a prime (14540040133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 333971 + ... + 374988.

It is an arithmetic number, because the mean of its divisors is an integer number (3635192400).

Almost surely, 2^14540040131 is an apocalyptic number.

14540040131 is a deficient number, since it is larger than the sum of its proper divisors (729469).

14540040131 is an equidigital number, since it uses as much as digits as its factorization.

14540040131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 729468.

The product of its (nonzero) digits is 960, while the sum is 23.

Adding to 14540040131 its reverse (13104004541), we get a palindrome (27644044672).

The spelling of 14540040131 in words is "fourteen billion, five hundred forty million, forty thousand, one hundred thirty-one".