14540040113 has 2 divisors, whose sum is σ = 14540040114. Its totient is φ = 14540040112.

The previous prime is 14540040107. The next prime is 14540040133. The reversal of 14540040113 is 31104004541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14513743729 + 26296384 = 120473^2 + 5128^2 .

It is a cyclic number.

It is not a de Polignac number, because 14540040113 - 2¹⁶ = 14539974577 is a prime.

It is a super-2 number, since 2×14540040113² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14540040133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7270020056 + 7270020057.

It is an arithmetic number, because the mean of its divisors is an integer number (7270020057).

Almost surely, 2^14540040113 is an apocalyptic number.

It is an amenable number.

14540040113 is a deficient number, since it is larger than the sum of its proper divisors (1).

14540040113 is an equidigital number, since it uses as much as digits as its factorization.

14540040113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 960, while the sum is 23.

Adding to 14540040113 its reverse (31104004541), we get a palindrome (45644044654).

The spelling of 14540040113 in words is "fourteen billion, five hundred forty million, forty thousand, one hundred thirteen".