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14540203103 = 71204791593
BaseRepresentation
bin11011000101010100…
…11110010001011111
31101112022221211220212
431202222132101133
5214234242444403
610402451003035
71023214454456
oct154252362137
941468854825
1014540203103
116191624888
12299959947b
1314a94cc09a
149bd135b9d
155a178d4d8
hex362a9e45f

14540203103 has 4 divisors (see below), whose sum is σ = 14744994768. Its totient is φ = 14335411440.

The previous prime is 14540203091. The next prime is 14540203121. The reversal of 14540203103 is 30130204541.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14540203103 - 24 = 14540203087 is a prime.

It is a super-2 number, since 2×145402031032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14540203603) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 102395726 + ... + 102395867.

It is an arithmetic number, because the mean of its divisors is an integer number (3686248692).

Almost surely, 214540203103 is an apocalyptic number.

14540203103 is a deficient number, since it is larger than the sum of its proper divisors (204791665).

14540203103 is an equidigital number, since it uses as much as digits as its factorization.

14540203103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 204791664.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 14540203103 its reverse (30130204541), we get a palindrome (44670407644).

The spelling of 14540203103 in words is "fourteen billion, five hundred forty million, two hundred three thousand, one hundred three".

Divisors: 1 71 204791593 14540203103