145410000553151 has 4 divisors (see below), whose sum is σ = 153963529997472. Its totient is φ = 136856471108832.

The previous prime is 145410000553079. The next prime is 145410000553157. The reversal of 145410000553151 is 151355000014541.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 145410000553151 - 2³⁸ = 145135122646207 is a prime.

It is a super-3 number, since 3×145410000553151³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (145410000553157) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4276764722135 + ... + 4276764722168.

It is an arithmetic number, because the mean of its divisors is an integer number (38490882499368).

Almost surely, 2^{145410000553151} is an apocalyptic number.

145410000553151 is a deficient number, since it is larger than the sum of its proper divisors (8553529444321).

145410000553151 is an equidigital number, since it uses as much as digits as its factorization.

145410000553151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8553529444320.

The product of its (nonzero) digits is 30000, while the sum is 35.

Adding to 145410000553151 its reverse (151355000014541), we get a palindrome (296765000567692).

The spelling of 145410000553151 in words is "one hundred forty-five trillion, four hundred ten billion, five hundred fifty-three thousand, one hundred fifty-one".