Base | Representation |
---|---|
bin | 100001000100000010100000… |
… | …001100111111100110111010 |
3 | 201001212100121222220010110122 |
4 | 201010002200030333212322 |
5 | 123024422012214043302 |
6 | 1233133504533413242 |
7 | 42425515121455424 |
oct | 4104024014774672 |
9 | 631770558803418 |
10 | 145413100534202 |
11 | 42373393381376 |
12 | 1438604919a222 |
13 | 631a520284687 |
14 | 27ca062a91814 |
15 | 11c27dd7b63a2 |
hex | 8440a033f9ba |
145413100534202 has 16 divisors (see below), whose sum is σ = 218263807285992. Its totient is φ = 72658504243200.
The previous prime is 145413100534201. The next prime is 145413100534223. The reversal of 145413100534202 is 202435001314541.
It can be written as a sum of positive squares in 4 ways, for example, as 84923578729201 + 60489521805001 = 9215399^2 + 7777501^2 .
It is a super-3 number, since 3×1454131005342023 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (145413100534201) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 46101452 + ... + 49154552.
Almost surely, 2145413100534202 is an apocalyptic number.
145413100534202 is a deficient number, since it is larger than the sum of its proper divisors (72850706751790).
145413100534202 is a wasteful number, since it uses less digits than its factorization.
145413100534202 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3068833.
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 145413100534202 its reverse (202435001314541), we get a palindrome (347848101848743).
The spelling of 145413100534202 in words is "one hundred forty-five trillion, four hundred thirteen billion, one hundred million, five hundred thirty-four thousand, two hundred two".
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