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145430130255 = 3513737061429
BaseRepresentation
bin1000011101110001001…
…1111010111001001111
3111220101021110002002120
42013130103322321033
54340320103132010
6150450520224023
713335615465564
oct2073423727117
9456337402076
10145430130255
11567495763a3
122422830b013
1310938881517
14707889886b
153bb27dde70
hex21dc4fae4f

145430130255 has 16 divisors (see below), whose sum is σ = 232857715680. Its totient is φ = 77506233728.

The previous prime is 145430130247. The next prime is 145430130269. The reversal of 145430130255 is 552031034541.

It is a cyclic number.

It is not a de Polignac number, because 145430130255 - 23 = 145430130247 is a prime.

It is a super-3 number, since 3×1454301302553 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3510120 + ... + 3551309.

It is an arithmetic number, because the mean of its divisors is an integer number (14553607230).

Almost surely, 2145430130255 is an apocalyptic number.

145430130255 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

145430130255 is a deficient number, since it is larger than the sum of its proper divisors (87427585425).

145430130255 is a wasteful number, since it uses less digits than its factorization.

145430130255 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7062810.

The product of its (nonzero) digits is 36000, while the sum is 33.

Adding to 145430130255 its reverse (552031034541), we get a palindrome (697461164796).

The spelling of 145430130255 in words is "one hundred forty-five billion, four hundred thirty million, one hundred thirty thousand, two hundred fifty-five".

Divisors: 1 3 5 15 1373 4119 6865 20595 7061429 21184287 35307145 105921435 9695342017 29086026051 48476710085 145430130255