Base | Representation |
---|---|
bin | 10101001010011100011… |
… | …100000101011011011011 |
3 | 12011000212022100021012202 |
4 | 111022130130011123123 |
5 | 142311423312212021 |
6 | 3032035041000415 |
7 | 210033331146356 |
oct | 25123434053333 |
9 | 5130768307182 |
10 | 1454323554011 |
11 | 510858806479 |
12 | 1b5a3602310b |
13 | a71b0322083 |
14 | 5056523529d |
15 | 27c6c38ca0b |
hex | 1529c7056db |
1454323554011 has 4 divisors (see below), whose sum is σ = 1467193674072. Its totient is φ = 1441453433952.
The previous prime is 1454323553981. The next prime is 1454323554053. The reversal of 1454323554011 is 1104553234541.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1454323554011 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1454353554011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6435059861 + ... + 6435060086.
It is an arithmetic number, because the mean of its divisors is an integer number (366798418518).
Almost surely, 21454323554011 is an apocalyptic number.
1454323554011 is a deficient number, since it is larger than the sum of its proper divisors (12870120061).
1454323554011 is a wasteful number, since it uses less digits than its factorization.
1454323554011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12870120060.
The product of its (nonzero) digits is 144000, while the sum is 38.
Adding to 1454323554011 its reverse (1104553234541), we get a palindrome (2558876788552).
The spelling of 1454323554011 in words is "one trillion, four hundred fifty-four billion, three hundred twenty-three million, five hundred fifty-four thousand, eleven".
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