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145443320311 = 654492222239
BaseRepresentation
bin1000011101110100011…
…0001111000111110111
3111220102012021012110011
42013131012033013313
54340331442222221
6150452111041051
713336135552552
oct2073506170767
9456365235404
10145443320311
1156755a65273
1224230810187
131093b51c0a3
14707a52d699
153bb3a471e1
hex21dd18f1f7

145443320311 has 4 divisors (see below), whose sum is σ = 145445608000. Its totient is φ = 145441032624.

The previous prime is 145443320261. The next prime is 145443320339. The reversal of 145443320311 is 113023344541.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 113023344541 = 169766601853.

It is a cyclic number.

It is not a de Polignac number, because 145443320311 - 211 = 145443318263 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (145443321311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1045671 + ... + 1176568.

It is an arithmetic number, because the mean of its divisors is an integer number (36361402000).

Almost surely, 2145443320311 is an apocalyptic number.

145443320311 is a deficient number, since it is larger than the sum of its proper divisors (2287689).

145443320311 is an equidigital number, since it uses as much as digits as its factorization.

145443320311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2287688.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 145443320311 its reverse (113023344541), we get a palindrome (258466664852).

The spelling of 145443320311 in words is "one hundred forty-five billion, four hundred forty-three million, three hundred twenty thousand, three hundred eleven".

Divisors: 1 65449 2222239 145443320311