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145451202203307 = 37112133196797211
BaseRepresentation
bin100001000100100101111111…
…001111010100111010101011
3201001222222222100220110112110
4201010211333033110322223
5123031033030231001212
61233203205420413403
742431334245351010
oct4104457717247253
9631888870813473
10145451202203307
1142388565814300
12143915013a7263
136320cb2c69000
1427cbc390ab707
1511c37bd7bea3c
hex84497f3d4eab

145451202203307 has 768 divisors, whose sum is σ = 286206452940800. Its totient is φ = 64113406156800.

The previous prime is 145451202203303. The next prime is 145451202203309. The reversal of 145451202203307 is 703302202154541.

It is not a de Polignac number, because 145451202203307 - 22 = 145451202203303 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (39).

It is not an unprimeable number, because it can be changed into a prime (145451202203303) by changing a digit.

It is a polite number, since it can be written in 767 ways as a sum of consecutive naturals, for example, 689342190432 + ... + 689342190642.

Almost surely, 2145451202203307 is an apocalyptic number.

145451202203307 is a deficient number, since it is larger than the sum of its proper divisors (140755250737493).

145451202203307 is a wasteful number, since it uses less digits than its factorization.

145451202203307 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 465 (or 428 counting only the distinct ones).

The product of its (nonzero) digits is 201600, while the sum is 39.

Adding to 145451202203307 its reverse (703302202154541), we get a palindrome (848753404357848).

The spelling of 145451202203307 in words is "one hundred forty-five trillion, four hundred fifty-one billion, two hundred two million, two hundred three thousand, three hundred seven".