Base | Representation |
---|---|
bin | 100001000101010100101001… |
… | …010111111101000111100111 |
3 | 201002011210021212001211010111 |
4 | 201011110221113331013213 |
5 | 123032343131103411403 |
6 | 1233242213000433451 |
7 | 42435056612152315 |
oct | 4105245127750747 |
9 | 632153255054114 |
10 | 145501301232103 |
11 | 423a7834375133 |
12 | 1439b163478887 |
13 | 632593839c44b |
14 | 27d042ca190b5 |
15 | 11c4c51bc656d |
hex | 8455295fd1e7 |
145501301232103 has 4 divisors (see below), whose sum is σ = 145501384980888. Its totient is φ = 145501217483320.
The previous prime is 145501301232083. The next prime is 145501301232139. The reversal of 145501301232103 is 301232103105541.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-145501301232103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (145501301292103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39211933 + ... + 42761878.
It is an arithmetic number, because the mean of its divisors is an integer number (36375346245222).
Almost surely, 2145501301232103 is an apocalyptic number.
145501301232103 is a deficient number, since it is larger than the sum of its proper divisors (83748785).
145501301232103 is an equidigital number, since it uses as much as digits as its factorization.
145501301232103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 83748784.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 145501301232103 its reverse (301232103105541), we get a palindrome (446733404337644).
The spelling of 145501301232103 in words is "one hundred forty-five trillion, five hundred one billion, three hundred one million, two hundred thirty-two thousand, one hundred three".
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