14550433433 has 4 divisors (see below), whose sum is σ = 15406341300. Its totient is φ = 13694525568.

The previous prime is 14550433423. The next prime is 14550433463. The reversal of 14550433433 is 33433405541.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 33433405541 = 353 ⋅94712197.

It can be written as a sum of positive squares in 2 ways, for example, as 5294454169 + 9255979264 = 72763^2 + 96208^2 .

It is a cyclic number.

It is not a de Polignac number, because 14550433433 - 2¹² = 14550429337 is a prime.

It is a super-2 number, since 2×14550433433² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14550433393 and 14550433402.

It is not an unprimeable number, because it can be changed into a prime (14550433423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 427953908 + ... + 427953941.

It is an arithmetic number, because the mean of its divisors is an integer number (3851585325).

Almost surely, 2^14550433433 is an apocalyptic number.

It is an amenable number.

14550433433 is a deficient number, since it is larger than the sum of its proper divisors (855907867).

14550433433 is an equidigital number, since it uses as much as digits as its factorization.

14550433433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 855907866.

The product of its (nonzero) digits is 129600, while the sum is 35.

Adding to 14550433433 its reverse (33433405541), we get a palindrome (47983838974).

The spelling of 14550433433 in words is "fourteen billion, five hundred fifty million, four hundred thirty-three thousand, four hundred thirty-three".