Base | Representation |
---|---|
bin | 10101001011011101110… |
… | …111110011101100100111 |
3 | 12011010200211000121002221 |
4 | 111023131313303230213 |
5 | 142321200330343310 |
6 | 3032340014213211 |
7 | 210102461163055 |
oct | 25133567635447 |
9 | 5133624017087 |
10 | 1455421340455 |
11 | 5112714496a5 |
12 | 1b60a17b4207 |
13 | a73268a9354 |
14 | 5062ad591d5 |
15 | 27cd3937ada |
hex | 152dddf3b27 |
1455421340455 has 4 divisors (see below), whose sum is σ = 1746505608552. Its totient is φ = 1164337072360.
The previous prime is 1455421340437. The next prime is 1455421340479. The reversal of 1455421340455 is 5540431245541.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1455421340455 - 29 = 1455421339943 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 145542134041 + ... + 145542134050.
It is an arithmetic number, because the mean of its divisors is an integer number (436626402138).
Almost surely, 21455421340455 is an apocalyptic number.
1455421340455 is a deficient number, since it is larger than the sum of its proper divisors (291084268097).
1455421340455 is an equidigital number, since it uses as much as digits as its factorization.
1455421340455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 291084268096.
The product of its (nonzero) digits is 960000, while the sum is 43.
Adding to 1455421340455 its reverse (5540431245541), we get a palindrome (6995852585996).
The spelling of 1455421340455 in words is "one trillion, four hundred fifty-five billion, four hundred twenty-one million, three hundred forty thousand, four hundred fifty-five".
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