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145632400153 = 1030314134951
BaseRepresentation
bin1000011110100001011…
…1100001001100011001
3111220220101001110020021
42013220113201030121
54341223343301103
6150522543430441
713343622656002
oct2075027411431
9456811043207
10145632400153
11568427697a9
1224283bb5421
131096b751a56
1470976ac1a9
153bc5445bbd
hex21e85e1319

145632400153 has 4 divisors (see below), whose sum is σ = 145646545408. Its totient is φ = 145618254900.

The previous prime is 145632400139. The next prime is 145632400157. The reversal of 145632400153 is 351004236541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 145632400153 - 221 = 145630303001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (145632400157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7057173 + ... + 7077778.

It is an arithmetic number, because the mean of its divisors is an integer number (36411636352).

Almost surely, 2145632400153 is an apocalyptic number.

It is an amenable number.

145632400153 is a deficient number, since it is larger than the sum of its proper divisors (14145255).

145632400153 is a wasteful number, since it uses less digits than its factorization.

145632400153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14145254.

The product of its (nonzero) digits is 43200, while the sum is 34.

Adding to 145632400153 its reverse (351004236541), we get a palindrome (496636636694).

The spelling of 145632400153 in words is "one hundred forty-five billion, six hundred thirty-two million, four hundred thousand, one hundred fifty-three".

Divisors: 1 10303 14134951 145632400153