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14563320207 = 34854440069
BaseRepresentation
bin11011001000000101…
…01010000110001111
31101120221110022121220
431210002222012033
5214311202221312
610405034254423
71023615115332
oct154402520617
941527408556
1014563320207
1161a3684027
1229a5287413
1314b1234247
149c2232619
155a3807c8c
hex3640aa18f

14563320207 has 4 divisors (see below), whose sum is σ = 19417760280. Its totient is φ = 9708880136.

The previous prime is 14563320199. The next prime is 14563320221. The reversal of 14563320207 is 70202336541.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 70202336541 = 323400778847.

It is a cyclic number.

It is not a de Polignac number, because 14563320207 - 23 = 14563320199 is a prime.

It is a super-2 number, since 2×145633202072 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14563320227) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2427220032 + ... + 2427220037.

It is an arithmetic number, because the mean of its divisors is an integer number (4854440070).

Almost surely, 214563320207 is an apocalyptic number.

14563320207 is a deficient number, since it is larger than the sum of its proper divisors (4854440073).

14563320207 is an equidigital number, since it uses as much as digits as its factorization.

14563320207 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4854440072.

The product of its (nonzero) digits is 30240, while the sum is 33.

Adding to 14563320207 its reverse (70202336541), we get a palindrome (84765656748).

The spelling of 14563320207 in words is "fourteen billion, five hundred sixty-three million, three hundred twenty thousand, two hundred seven".

Divisors: 1 3 4854440069 14563320207