Base | Representation |
---|---|
bin | 10101001100101001000… |
… | …101001111011011110001 |
3 | 12011020221202100022200222 |
4 | 111030221011033123301 |
5 | 142331241341400022 |
6 | 3033105131222425 |
7 | 210145652335202 |
oct | 25145105173361 |
9 | 5136852308628 |
10 | 1456683153137 |
11 | 5118597341a3 |
12 | 1b63942a7a15 |
13 | a7498133884 |
14 | 5070a7795a9 |
15 | 27d595d3242 |
hex | 1532914f6f1 |
1456683153137 has 4 divisors (see below), whose sum is σ = 1456688862720. Its totient is φ = 1456677443556.
The previous prime is 1456683153131. The next prime is 1456683153139. The reversal of 1456683153137 is 7313513866541.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1456683153137 - 26 = 1456683153073 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1456683153131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2453273 + ... + 2988630.
It is an arithmetic number, because the mean of its divisors is an integer number (364172215680).
Almost surely, 21456683153137 is an apocalyptic number.
It is an amenable number.
1456683153137 is a deficient number, since it is larger than the sum of its proper divisors (5709583).
1456683153137 is an equidigital number, since it uses as much as digits as its factorization.
1456683153137 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5709582.
The product of its digits is 5443200, while the sum is 53.
The spelling of 1456683153137 in words is "one trillion, four hundred fifty-six billion, six hundred eighty-three million, one hundred fifty-three thousand, one hundred thirty-seven".
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